16x^2+30x-276=0

Solution for 16x^2+30x-276=0 equation:

16x^2+30x-276=0

a = 16; b = 30; c = -276;
Δ = b2-4ac
Δ = 302-4·16·(-276)
Δ = 18564
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18564}=\sqrt{4*4641}=\sqrt{4}*\sqrt{4641}=2\sqrt{4641}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{4641}}{2*16}=\frac{-30-2\sqrt{4641}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{4641}}{2*16}=\frac{-30+2\sqrt{4641}}{32}
$